If a 360-year cycle is used instead of the 60-year cycle, the formula for the 1st remainder becomes (360*c + y)*L mod Y < L where L=2519=7*360-1 and Y=6840=19*360.
The 360-year Cycle of the Meyer-
Palmen Soli-lunar Calendarby Karl Palmen
(360*c + y)*L mod Y can be expressed as
( 3960*c + y*L ) mod Y Noting that 3960 = 11*360, L is 7*360 - 1 and Y is 19*360 we have
( 360*( 11*c + 7*y mod 19) - y ) mod Y From this we can obtain this remainder modulo 360 (which I call b). It is
b = (-y) mod Y Because y is between 1 and 360 inclusive it is
b = 360-y If this is subtracted from the full remainder one gets
(360*(11*c+7*y mod 19) - 360 ) mod Y which is
360*( 11*c+7*y - 1 mod 19 ) which gives the 360s part of the remainder a as
a = 11*c + 7*y - 1 mod 19 The long years are those years for which a<7, except year 00-001 for which the remainder is L, giving a=6 and b=359.
Last modified: 1999-05-05 CE / 102-25-02-21 MP
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